Return the floating point remainder of x / y.

This function is compatible with the following targets:

ANSI

BeOS

EMB/RTOS

Mac OS

Palm OS

Win32

#include <math.h>

double fmod(double x, double y);

float fmodf(float, float);

long double fmodl(long double, long double);

Parameters for this function are:

x	double, float or long double	The value to compute
y	double, float or long double	The divider

fmod() returns, when possible, the value f such that x = i y + f for some integer i, and |f| < |y|. The sign of f matches the sign of x.

"floor"

"ceil"

"fmod"

"fabs"

#include <math.h>
#include <stdio.h>

int main(void)
{
	double x = -54.4, y = 10.0;
	printf("Remainder of %f / %f = %f.\n",	x, y, fmod(x, y));

	return 0;
}
Output:
Remainder of -54.400000 / 10.000000 = -4.400000.      





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Last updated: August 16, 2000