Separate integer and fractional parts.

This function is compatible with the following targets:

ANSI

BeOS

EMB/RTOS

Mac OS

Palm OS

Win32

#include <math.h>

double modf(double value, double *iptr);

float fmodf(float value, float *iptr);

long double modfl(long double value, 

Parameters for this function are:

value	double, float, or long double	The value to separate
iptr	double, float, or long double	integer part

The modf() function separates value into its integer and fractional parts. In other words, modf() separates value such that value = f + i where 0 £ f < 1, and i is the largest integer that is not greater than value.

modf() returns the signed fractional part of value, and stores the integer part in the integer pointed to by iptr.

"frexp"

"ldexp"

#include <math.h>
#include <stdio.h>

int main(void)
{
	double i, f, value = 27.04;
	
	f = modf(value, &i);
	printf("The fractional part of %f is %f.\n", value, f);
	printf("The integer part of %f is %f.\n", value, i);

	return 0;
}
Output:
The fractional part of 27.040000 is 0.040000.
The integer part of 27.040000 is 27.000000.





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Last updated: August 16, 2000