Compare two character arrays according to locale.

This function is compatible with the following targets:

ANSI

BeOS

EMB/RTOS

Mac OS

Palm OS

Win32

#include <string.h>

int strcoll(const char *s1, const char *s2);

Parameters for this facility are:

s1	const char *	The string to compare
s2	const char *	The comparison string

The strcoll() function compares two character arrays based on the collating sequence set by the locale.h header file.

The Metrowerks C implementation of strcoll() compares two character arrays using strcmp(). It is included in the string library to conform to the ANSI C Standard Library specification.

strcoll() returns zero if s1 is equal to s2, a negative value if s1 is less than s2, and a positive value if s1 is greater than s2.

"Locale specification"

"memcmp"

"strcmp"

"strncmp",

#include <string.h>
#include <stdio.h>

int main(void)
{
	static char s1[] = "aardvark", s2[] = "xylophone";
	int result;
	
	result = strcoll(s1, s2);

	if (result < 1)
		printf("%s is less than %s\n", s1, s2);
	else
		printf("%s is equal or greater than %s\n", s1, s2);

	return 0;
}
Output:
aardvark is less than xylophone





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Last updated: August 16, 2000